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x^2-92x-1120=0
a = 1; b = -92; c = -1120;
Δ = b2-4ac
Δ = -922-4·1·(-1120)
Δ = 12944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12944}=\sqrt{16*809}=\sqrt{16}*\sqrt{809}=4\sqrt{809}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-4\sqrt{809}}{2*1}=\frac{92-4\sqrt{809}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+4\sqrt{809}}{2*1}=\frac{92+4\sqrt{809}}{2} $
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